15x^2=14x+8

Solution for 15x^2=14x+8 equation:

15x^2=14x+8

We move all terms to the left:

15x^2-(14x+8)=0

We get rid of parentheses

15x^2-14x-8=0

a = 15; b = -14; c = -8;
Δ = b2-4ac
Δ = -142-4·15·(-8)
Δ = 676
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{676}=26$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-26}{2*15}=\frac{-12}{30}
=-2/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+26}{2*15}=\frac{40}{30}
=1+1/3
$